It should be easy to observe that
z must be odd. We are looking for positive integer solution to

By manually doing division algorithm once, you can show that

. Simultaneously, you can find a particular integer solution to

, which is


Now, set

Then we have


as general solution. To keep
x and
y both positive, we may have a "sense" that when

is small, we can adjust
K to keep
x small but positive, and hence "allow room" for
y to be positive.
Take

, we have

. However,

. The remainder 1651 is too large to be
x.
Now observe that when
z is increased by 2,
a drops by 4609. Notice

. That means when we increase
z by 2,

drops by 537.
Increase
z from 1 to 7,

drops from 1651 to

. Setting

, we get

. A possible solution is given by


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