試想出一個策略,使得無論我寫下那兩個實數,你估中的機會都大於 1/2。
(e.g. 估中的話在 MD Academic seminar 中有優先座位選擇權 ^^)
驟眼看,也許你會想:(車!) 我怎樣估也只得 1/2 機會估中。此策略沒理由存在!
但我告訴你,它是存在的! 看答案前再想一想吧。
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其中一個策略如下:
Construct a strictly increasing function f(x) from the real line to the open interval (0, 1).
For example, f(x) can be
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiHka-4rc2Su82Nzm3oT6pGMJiMQep_gcTmnmV38XpVINRA8ktFNlSXGrIEtq2yauKhBYAdbsgiWcVaOr8gu9DST97GTeEpB8x_vf7tF-jt5tBXCVTXQvbqG3ioUkY0HCC8oHLYFyT9p1zF/s320/eq1.bmp)
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjn9ZDu8T8oQYrczYtSTA7epG9Kg03ufn3CSC4_o1jhjtMLUS4AsFhBCBUtA-wF0kcHZ2TnZoP40dSB-U-h_G6PNr-J3QRivXkyKPqkz2rBe8ZfJ1-0dp2HWB3emeW7SgSzVaaZney2PufE/s320/eq2.bmp)
The strategy is simple:
If the number you picked is x, guess that it is larger with probability f(x).
Here' s how you can do it "practically": After you see the number, say x, create a coin which has probability f(x) to show up head and 1-f(x) to show up tail, and then flip it. Then you guess "x is bigger" if head shows up, and guess "x is smaller" if tail shows up.
Suppose the number I wrote are a and b, where a
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiddZvaftS170Ww2ljtSiAv5GwSf0QGQ66JPSdYNesPLJiAd39AlTX7U9q9VOUgfq-Vf7c_jtRYnZjctVEyKJzVYjHT76Js-O117cekH_WTtWTERfhBuUMMdsDLg75bDoCIMf1zJLwXmJqg/s320/eq3.bmp)
The interesting thing in the above strategy is:
Even if you look at the number x, you do not know whether you'll guess "larger" or "smaller" until you've flipped the coin. This is a so called "Probabilistic Strategy".
若你想知多一點有關概率的問題,萬勿錯過 12 月 28 日(星期日)的 MD Academic seminar !
p.s. 此問題與 MD Academic seminar 無關,如有雷同,實屬巧合。
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